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Why can two expressions for yyy be equated?
A
They are equal to the same value of yyy.
B
Substituting y=7−2xy=7-2xy=7−2x into x2+y2=13x^2+y^2=13x2+y2=13 gives x2+(7−2x)2=13x^2+(7-2x)^2=13x2+(7−2x)2=13, which simplifies to 5x2−28x+36=0\boxed{5x^2-28x+36=0}5x2−28x+36=0.
C
Substituting y=7−2xy=7-2xy=7−2x into x2+y2=13x^2+y^2=13x2+y2=13 gives x2+(7−2x)2=13\boxed{x^2+(7-2x)^2=13}x2+(7−2x)2=13, which simplifies to 5x2−28x+36=05x^2-28x+36=05x2−28x+36=0.
D
- (1,1)(1,1)(1,1)
- (2,4)(2,4)(2,4)
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1.2.7 One linear one quadratic simultaneous equations Flashcards
24 flashcards on OCR (MEI) A Level Maths 1.2.7 One linear one quadratic simultaneous equations: the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.