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3.5 Newton's Laws of Motion

3.5 Newton's Laws of Motion

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Question 9

A particle of mass m m\,m kg is in equilibrium. A force (−7i+73j)(-7\mathbf{i}+7\sqrt3\mathbf{j})(−7i+73​j) N acts on it, together with a horizontal force FiF\mathbf{i}Fi N and its weight. The unit vector j\mathbf{j}j is vertically upwards. Use g=9.8 m s−2g=9.8\text{ m s}^{-2}g=9.8 m s−2.

a.

Find FFF.

[2]
b.

Find mmm.

[2]
c.

State the resultant force acting on the particle.

[1]
Markscheme

3.5 Newton's Laws of Motion Questions

  1. A Level
  2. /Maths
  3. /3.5 Newton's Laws of Motion

49 exam-style questions on OCR (MEI) A Level Maths 3.5 Newton's Laws of Motion, covering 3.5.1 Meaning of Newton's three laws, 3.5.2 Equation of motion, 3.5.3 Equation of motion for a particle in a straight line, 3.5.4 Model a system of connected particles, 3.5.5 Equations of motion for individual particles, 3.5.6 System with no relative motion as a single particle, and 3.5.7 Equation of motion in a straight line or plane (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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