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3.3.1 Model motion under gravity using vectors (A-level only)

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Why is horizontal acceleration zero in the standard projectile model?

A

It decreases by g m s−1g\text{ m s}^{-1}g m s−1.

B

For launch from the origin at speed uuu and angle θ\thetaθ, r(t)=(utcos⁡θutsin⁡θ−12gt2)\boxed{\mathbf r(t)=\begin{pmatrix}ut\cos\theta\\ut\sin\theta-\frac12gt^2\end{pmatrix}}r(t)=(utcosθutsinθ−21​gt2​)​.

C

Gravity acts vertically and air resistance is ignored.

D

(10310) m s−1\begin{pmatrix}10\sqrt3\\10\end{pmatrix}\text{ m s}^{-1}(103​10​) m s−1

Card 1 of 20

3.3.1 Model motion under gravity using vectors (A-level only) Flashcards

  1. A Level
  2. /Maths
  3. /3.3.1 Model motion under gravity using vectors (A-level only)

20 flashcards on OCR (MEI) A Level Maths 3.3.1 Model motion under gravity using vectors (A-level only): the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.

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