A particle P P\,P travels along a straight line such that at time t t\,t seconds, t≥0t \geq 0t≥0, after leaving the point O O\,O on the line, the velocity of PPP, v v\,v ms−1^{-1}−1, is modelled as
v=3t+5−2t2 v = 3t + 5 - 2t^2 v=3t+5−2t2Find the value of t t\,t at the point when P P\,P stops accelerating.
Find the distance of P P\,P from O O\,O at the instant when P P\,P changes its direction of motion.
