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1.9.27 Integration by substitution (reverse chain rule) (A-level only)

1.9.27 Integration by substitution (reverse chain rule) (A-level only)

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Question 8

Evaluate the following indefinite integrals:

i.
∫x2−9x3−27x+1 dx \int \frac{x^2 - 9}{x^3 - 27x + 1} \, \mathrm{d}x ∫x3−27x+1x2−9​dx
[2]
ii.
∫13e2x(e2x−5)6 dx \int \frac{13 \mathrm{e}^{2x}}{(\mathrm{e}^{2x} - 5)^6} \, \mathrm{d}x ∫(e2x−5)613e2x​dx
[3]
Markscheme

1.9.27 Integration by substitution (reverse chain rule) (A-level only) Questions

  1. A Level
  2. /Maths
  3. /1.9.27 Integration by substitution (reverse chain rule) (A-level only)

36 exam-style questions on OCR (MEI) A Level Maths 1.9.27 Integration by substitution (reverse chain rule) (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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