The point P(−6,−4)P(-6, -4)P(−6,−4) lies on the curve with equation y=f(x)y = f(x)y=f(x), x∈Rx \in \mathbb{R}x∈R.
Find the coordinates of the point to which PPP is mapped when the curve with equation y=f(x)y = f(x)y=f(x) is transformed to the curve with equation:
y=f(3x)y = f(3x)y=f(3x)
y=2f(x+2)y = 2f(x + 2)y=2f(x+2)
y=∣f(x)∣y = |f(x)|y=∣f(x)∣
33 exam-style questions on OCR (MEI) A Level Maths 1.4 Graphs, covering 1.4.1 Graphs of functions, 1.4.2 Intersection points with axes, 1.4.3 Completing the square for a quadratic curve, 1.4.4 Sketch graphs of simple functions, 1.4.5 Stationary points when curve sketching, 1.4.6 Graphs of reciprocal-type functions, 1.4.7 Single transformations of graphs, 1.4.8 Combined transformations of graphs (A-level only), and 1.4.9 Stationary points of inflection (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.