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1.5.16 Gradient of a parametric curve (A-level only)

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In x=f(t)x=f(t)x=f(t) and y=g(t)y=g(t)y=g(t), ttt is the [     ] that determines both coordinates.

A

dydx=dy/dtdx/dt\dfrac{dy}{dx}=\dfrac{dy/dt}{dx/dt}dxdy​=dx/dtdy/dt​

B

A line through (x1,y1)(x_1,y_1)(x1​,y1​) with gradient mmm has equation y−y1=m(x−x1)\boxed{y-y_1=m(x-x_1)}y−y1​=m(x−x1​)​.

C

If dxdt=0\dfrac{dx}{dt}=0dtdx​=0 but dydt≠0\dfrac{dy}{dt}\neq0dtdy​=0, the curve usually has a vertical tangent.

D

In x=f(t)x=f(t)x=f(t) and y=g(t)y=g(t)y=g(t), ttt is the parameter that determines both coordinates.

Card 1 of 22

1.5.16 Gradient of a parametric curve (A-level only) Flashcards

  1. A Level
  2. /Maths
  3. /1.5.16 Gradient of a parametric curve (A-level only)

22 flashcards on OCR (MEI) A Level Maths 1.5.16 Gradient of a parametric curve (A-level only): the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.

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