Card 1 of 20
For y=kxny=kx^ny=kxn, the power rule gives [...]\text{[...]}[...].
A
A variable in a denominator is rewritten using a negative power before differentiation.
B
For y=kxny=kx^ny=kxn, the power rule gives dydx=knxn−1\boxed{\dfrac{dy}{dx}=knx^{n-1}}dxdy=knxn−1.
C
dydx=12x1/2\dfrac{dy}{dx}=12x^{1/2}dxdy=12x1/2
D
When reducing a fractional index, 23−1=\dfrac{2}{3}-1=32−1= −13\boxed{-\dfrac{1}{3}}−31.
Card 1 of 20
1.9.5 Differentiate y = kx^n Flashcards
20 flashcards on OCR (MEI) A Level Maths 1.9.5 Differentiate y = kx^n: the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.