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1.2 Algebra

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Question 14
69%

Express 3x3+14x2+19x+8(x+2)(x+3)\displaystyle \frac{3x^3+14x^2+19x+8}{(x+2)(x+3)}(x+2)(x+3)3x3+14x2+19x+8​ in the form Ax+B+C(x+2)+D(x+3)\displaystyle Ax+B + \frac{C}{(x+2)} + \frac{D}{(x+3)}Ax+B+(x+2)C​+(x+3)D​

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1.2 Algebra Questions

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