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1.8.8 Integration by substitution (A-level only)

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Question 25

Use the substitution u=1+2exu = 1 + 2e^xu=1+2ex to find ∫e3x1+2exdx\displaystyle \int \frac{e^{3x}}{1 + 2e^x} dx∫1+2exe3x​dx.

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1.8.8 Integration by substitution (A-level only) Questions

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