celeration formulae Flashcards","topicId":"7cd81e46-8910-4cf6-bce8-4d2df850da1d","topicSlug":"constant-acceleration-formulae","cards":[{"id":"dd0ef312-452d-4f62-b85a-b5a557449d1e","cardType":"basic","front":"When does an object slow down?","back":"When velocity and acceleration have opposite signs.","points":1,"mcqOptions":null},{"id":"5621bc3d-2a76-455b-9dec-2694feceadbf","cardType":"basic","front":"If upwards is positive, what sign does a falling object's velocity have?","back":"The velocity is negative.","points":1,"mcqOptions":null},{"id":"4f47c8fd-745a-44e8-97ed-7b4c100fce4f","cardType":"basic","front":"If upwards is positive, what is the acceleration due to gravity?","back":"$a=-9.8\\text{ m s}^{-2}$.","points":1,"mcqOptions":null},{"id":"4fc557b6-268b-41f3-8c56-b3032cd9b707","cardType":"basic","front":"What is the velocity at the instant an object stops?","back":"$v=0$.","points":1,"mcqOptions":null},{"id":"cadff0e3-bbef-46e4-9592-a1b3702d703d","cardType":"basic","front":"At maximum height, what is a projectile's instantaneous velocity?","back":"$v=0$.","points":1,"mcqOptions":null},{"id":"7be3e55b-9a5b-4c87-aece-a189ead5e137","cardType":"basic","front":"At maximum height, what is a projectile's acceleration if upwards is positive?","back":"It remains $-9.8\\text{ m s}^{-2}$.","points":1,"mcqOptions":null},{"id":"089e427e-08aa-441c-948d-25d5c7cc178e","cardType":"basic","front":"What does the gradient of a velocity-time graph represent?","back":"Acceleration.","points":1,"mcqOptions":null},{"id":"d111b0de-f566-434b-81e1-2bab353286dd","cardType":"basic","front":"What does the signed area under a velocity-time graph represent?","back":"Displacement.","points":1,"mcqOptions":null},{"id":"5032a386-a1c1-493f-8a7b-90afef51537c","cardType":"basic","front":"Why is a velocity-time graph a straight line during constant acceleration?","back":"Velocity changes by equal amounts in equal times.","points":2,"mcqOptions":null},{"id":"34764d6a-fd65-44fc-acfb-f0810e529123","cardType":"cloze","front":"For constant acceleration, $\\text{[...]}$.","back":"For constant acceleration, $\\boxed{v=u+at}$.","points":null,"mcqOptions":null},{"id":"ec099c72-532f-441f-aded-e96d33cfc0fd","cardType":"cloze","front":"When final velocity is not involved, use $\\text{[...]}$.","back":"When final velocity is not involved, use $\\boxed{s=ut+\\frac{1}{2}at^2}$.","points":null,"mcqOptions":null},{"id":"2a4ef132-60f8-4bef-a275-09373d0d2fef","cardType":"cloze","front":"When initial velocity is not involved, use $\\text{[...]}$.","back":"When initial velocity is not involved, use $\\boxed{s=vt-\\frac{1}{2}at^2}$.","points":null,"mcqOptions":null},{"id":"0286a402-9ffd-4287-a721-05480a15d4f2","cardType":"cloze","front":"When acceleration is not involved, use $\\text{[...]}$.","back":"When acceleration is not involved, use $\\boxed{s=\\frac{1}{2}(u+v)t}$.","points":null,"mcqOptions":null},{"id":"7ff92e2e-0cea-4692-8ada-4450bc5cc8f8","cardType":"cloze","front":"When time is not involved, use $\\text{[...]}$.","back":"When time is not involved, use $\\boxed{v^2=u^2+2as}$.","points":null,"mcqOptions":null},{"id":"21d6ae27-477e-4d98-a483-ec21c3e8ca2d","cardType":"cloze","front":"Under constant acceleration, average velocity is $\\text{[...]}$.","back":"Under constant acceleration, average velocity is $\\boxed{\\frac{u+v}{2}}$.","points":null,"mcqOptions":null},{"id":"d463864a-2019-4045-81b7-f09e95f06846","cardType":"basic","front":"How is $s=ut+\\frac{1}{2}at^2$ obtained from a velocity-time graph?","back":"Add the areas: rectangle $ut$ and triangle $\\frac{1}{2}at^2$.","points":2,"mcqOptions":null},{"id":"0668d5ed-af2c-4824-b8bf-f553b52d2d4a","cardType":"basic","front":"How is time eliminated when deriving $v^2=u^2+2as$?","back":"Substitute $t=\\frac{v-u}{a}$ into $s=\\frac{1}{2}(u+v)t$.","points":2,"mcqOptions":null},{"id":"cc4a7775-513c-4cac-8

3.2.4 Constant acceleration formulae Flashcards

3.2.4 Constant acceleration formulae Flashcards