Determine ddxln(sec43x)\frac{d}{dx}\ln(\sec^4 3x)dxdln(sec43x), giving your answer in its simplest form.
Differentiate (3x2−4)3(3x^2 - 4)^3(3x2−4)3 with respect to xxx.
Hence show that
∫02x(3x2−4)2 dx=K \int_{0}^{2} x(3x^2 - 4)^2 \, dx = K ∫02x(3x2−4)2dx=Kwhere KKK is an integer to be found.
(Solutions relying on calculator technology are not acceptable.)