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1.7.18 Chain rule (A-level only)

1.7.18 Chain rule (A-level only)

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Question 49

An industrial chemical reactor vessel with a circular cross-section and a maximum depth of 30 cm is initially empty. A cooling reagent is pumped into the reactor such that its depth at time ttt seconds is hhh cm.

The volume of reagent in the reactor, V cm3V \text{ cm}^3V cm3, is modelled by the formula:

V=112h2(2h+45)0≤h≤30 V = \frac{1}{12}h^2(2h + 45) \quad 0 \le h \le 30 V=121​h2(2h+45)0≤h≤30

The reagent is delivered at a constant rate of 225 cm3 s−1225 \text{ cm}^3\text{ s}^{-1}225 cm3 s−1. According to this model:

a.

Determine the time required to fill the reactor vessel completely.

[2]
b.

Calculate the rate of change of the depth of the reagent, in cm s−1\text{cm s}^{-1}cm s−1, at the instant the depth reaches 15 cm.

[5]
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1.7.18 Chain rule (A-level only) Questions

  1. A Level
  2. /Maths
  3. /1.7.18 Chain rule (A-level only)

74 exam-style questions on OCR A Level Maths 1.7.18 Chain rule (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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