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1.4.8 Arithmetic sequences and series (A-level only)

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Question 15

An arithmetic sequence has first term aaa and common difference ddd.

The sum of the first 9 terms of the sequence is equal to the square of the sum of the first 3 terms.

a.

Show that a+4d=a2+2ad+d2a + 4d = a^2 + 2ad + d^2a+4d=a2+2ad+d2

[4]
b.

Given that the fifth term of the sequence is 9, find the smallest possible value of aaa.

[4]

1.4.8 Arithmetic sequences and series (A-level only) Questions

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