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Why does including either endpoint not change a class width?

A

3510=3.5\frac{35}{10}=3.51035​=3.5

B

For a histogram bar, frequency=class width×frequency density\boxed{\text{frequency}=\text{class width}\times\text{frequency density}}frequency=class width×frequency density​.

C

Unequal widths mean a shorter bar may have a greater area.

D

Width depends only on the difference between the class boundaries.

Card 1 of 20

2.2.2 Area in a histogram Flashcards

  1. A Level
  2. /Maths
  3. /2.2.2 Area in a histogram

20 flashcards on OCR A Level Maths 2.2.2 Area in a histogram: the key formulae, methods and definitions you need to recall for Paper 1, Paper 2 and Paper 3.

Flashcards