A circle has equation (x+8)2+(y−15)2=289(x + 8)^2 + (y - 15)^2 = 289(x+8)2+(y−15)2=289.
Find the gradient of the tangent to the circle at the origin.
292 exam-style questions on Edexcel A Level Maths Circles, covering 6.1 Midpoints and Perpendicular Bisectors, 6.2 Equation of a Circle, 6.3 Intersections of Straight Lines and Circles, 6.4 Use Tangent and Chord Properties, and 6.5 Circles and Triangles. Each one has a worked solution and a mark scheme showing where the marks go.