The roots of the equation x2+kx−10=0x^2+kx-10=0x2+kx−10=0 are x=−k2±k24+10\displaystyle x=-\frac{k}{2}\pm\sqrt{\frac{k^2}{4}+10}x=−2k±4k2+10.
Hence find the exact roots of the equation x2+6x−10=0x^2 + 6x - 10 = 0x2+6x−10=0
211 exam-style questions on Edexcel A Level Maths Quadratics, covering 2.1 Solving Quadratics, 2.2 Completing the Square, 2.3 Sketching Quadratic Graphs, 2.4 The Discriminant, and 2.5 Modelling with Quadratics. Each one has a worked solution and a mark scheme showing where the marks go.