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Exponentials and Logarithms

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Question 64

Solve the equation, giving your answers in exact form, where k>0 k>0\,k>0 and k≠1k\ne1k=1.

2ey+2ke−y=2(k+1) 2e^y + 2ke^{-y} = 2(k+1) 2ey+2ke−y=2(k+1)
[5]
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Exponentials and Logarithms Questions

  1. A Level
  2. /Maths
  3. /Exponentials and Logarithms

277 exam-style questions on Edexcel A Level Maths Exponentials and Logarithms, covering 14.1 Exponential Functions, 14.2 y = e^x, 14.3 Exponential Modelling, 14.4 Logarithms, 14.5 Laws of Logarithms, 14.6 Solving Equations using Logarithms, 14.7 Working with Natural Logarithms, and 14.8 Logarithms and Non-Linear Data. Each one has a worked solution and a mark scheme showing where the marks go.

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