Given that the area enclosed by xxx-axis and the curve with equation y=(x+a)(x−1)2y = (x + a)(x - 1)^2y=(x+a)(x−1)2, where a>0a>0a>0, is 643\displaystyle \frac{64}{3}364 square units, use integration to find the value of aaa.
411 exam-style questions on Edexcel A Level Maths Integration, covering 13.1 Integrating x^n, 13.2 Indefinite Integrals, 13.3 Finding Functions, 13.4 Definite Integrals, 13.5 Areas under Curves, 13.6 Areas under the x-axis, and 13.7 Areas between curves and lines. Each one has a worked solution and a mark scheme showing where the marks go.