A particle P P\,P moves in a straight line so that, at time t t\,t seconds, its velocity v m s−1v \text{ m s}^{-1}v m s−1 is given by
v={6t−t20≤t≤612−2tt>6 v = \begin{cases} 6t - t^2 & 0 \leq t \leq 6 \\ 12 - 2t & t > 6 \end{cases} v={6t−t212−2t0≤t≤6t>6Find the acceleration of P P\,P when t=4t = 4t=4.
Find the total distance traveled by P P\,P in the first 12 seconds.
308 exam-style questions on Edexcel A Level Maths Variable Acceleration, covering 11.1 Functions of Time, 11.2 Using Differentiation, 11.3 Maxima and Minima Problems, 11.4 Using Integration, and 11.5 Constant Acceleration Formulae. Each one has a worked solution and a mark scheme showing where the marks go.