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Constant Acceleration

Constant Acceleration

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Question 119

A particle moves from A to B under constant acceleration.
The distance between A and B is sss.
The speed at A is uuu. The speed at B is vvv.
The time taken is ttt.
The acceleration is aaa.

Given s=72 ms = 72 \text{ m}s=72 m, u=0 ms−1u = 0 \text{ ms}^{-1}u=0 ms−1, v=24 ms−1v = 24 \text{ ms}^{-1}v=24 ms−1. Find a a\,a and ttt.

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Markscheme

Constant Acceleration Questions

  1. A Level
  2. /Maths
  3. /Constant Acceleration

197 exam-style questions on Edexcel A Level Maths Constant Acceleration, covering 8.2 Modelling Assumptions, 8.3 Quantities and Units, 8.4 Working with Vectors, 9.1 Displacement-Time Graphs, 9.2 Velocity-Time Graphs, 9.3 Constant Acceleration Formulae 1, 9.4 Constant Acceleration Formulae 2, and 9.5 Vertical Motion Under Gravity. Each one has a worked solution and a mark scheme showing where the marks go.

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