A particle moves from A to B under constant acceleration.
The distance between A and B is sss.
The speed at A is uuu. The speed at B is vvv.
The time taken is ttt.
The acceleration is aaa.
Given s=160 ms = 160 \text{ m}s=160 m, a=2 ms−2a = 2 \text{ ms}^{-2}a=2 ms−2, v=28 ms−1v = 28 \text{ ms}^{-1}v=28 ms−1. Find t t\,t and uuu.
123 exam-style questions on Edexcel A Level Maths Constant Acceleration, covering 8.2 Modelling Assumptions, 8.3 Quantities and Units, 8.4 Working with Vectors, 9.1 Displacement-Time Graphs, 9.2 Velocity-Time Graphs, 9.3 Constant Acceleration Formulae 1, 9.4 Constant Acceleration Formulae 2, and 9.5 Vertical Motion Under Gravity. Each one has a worked solution and a mark scheme showing where the marks go.