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2.4 Probability Formulae

2.4 Probability Formulae

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Question 3

The events A A\,A and B B\,B are such that P(A)=310\displaystyle P(A) = \frac{3}{10}P(A)=103​, P(A∩B)=325\displaystyle P(A \cap B) = \frac{3}{25}P(A∩B)=253​, P(A∣B)=25\displaystyle P(A|B) = \frac{2}{5}P(A∣B)=52​. Find

a.

P(B)P(B)P(B)

[3]
b.

P(A∪B)P(A \cup B)P(A∪B)

[3]
c.

P(B∣A′)P(B|A')P(B∣A′)

[3]
Markscheme

2.4 Probability Formulae Questions

  1. A Level
  2. /Maths
  3. /2.4 Probability Formulae

29 exam-style questions on Edexcel A Level Maths 2.4 Probability Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

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