The events X X\,X and Y Y\,Y are such that P(X)=0.6P(X) = 0.6P(X)=0.6, P(Y)=0.25P(Y) = 0.25P(Y)=0.25 and P(X∣Y)=0.4P(X|Y) = 0.4P(X∣Y)=0.4.
Find P(X∩Y)P(X \cap Y)P(X∩Y).
Find P(Y′∣X)P(Y'|X)P(Y′∣X).
Find P(X′∪Y)P(X' \cup Y)P(X′∪Y).
Determine whether the events X X\,X and Y Y\,Y are independent, give a reason for your answer.
368 exam-style questions on Edexcel A Level Maths Conditional Probability, covering 2.1 Set Notation, 2.2 Conditional Probability, 2.3 Conditional Probabilities in Venn Diagrams, 2.4 Probability Formulae, and 2.5 Tree Diagrams. Each one has a worked solution and a mark scheme showing where the marks go.