Show that
2cosx−secx=cos2xcosx 2\cos x-\sec x=\frac{\cos 2x}{\cos x} 2cosx−secx=cosxcos2xHence prove the identity:
2sinx2cosx−secx≡tan2x \frac{2\sin x}{2\cos x-\sec x}\equiv\tan 2x 2cosx−secx2sinx≡tan2x348 exam-style questions on Edexcel A Level Maths Trigonometry and Modelling, covering 7.1 Addition Formulae, 7.2 Double Angle Formulae, 7.3 Solving Trigonometric Equations, 7.4 Simplifying a cos x +- b sin x, 7.5 Proving Trigonometric Identities, and 7.6 Modelling with Trigonometric Functions. Each one has a worked solution and a mark scheme showing where the marks go.