The point P(−6,−4)P(-6, -4)P(−6,−4) lies on the curve with equation y=f(x)y = f(x)y=f(x), x∈Rx \in \mathbb{R}x∈R.
Find the coordinates of the point to which PPP is mapped when the curve with equation y=f(x)y = f(x)y=f(x) is transformed to the curve with equation:
y=f(3x)y = f(3x)y=f(3x)
y=2f(x+2)y = 2f(x + 2)y=2f(x+2)
y=∣f(x)∣y = |f(x)|y=∣f(x)∣
471 exam-style questions on Edexcel A Level Maths Functions and Graphs, covering 2.1 The Modulus Function, 2.2 Functions and Mappings, 2.3 Composite Functions, 2.4 Inverse Functions, 2.5 y=|f(x)| and y=f(|x|), 2.6 Combining Transformations, and 2.7 Solving Modulus Problems. Each one has a worked solution and a mark scheme showing where the marks go.