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11.9 The Trapezium Rule

11.9 The Trapezium Rule

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Question 42

A research drone monitors the rate of data transmission, D(t)D(t)D(t), in gigabits per hour, from a remote sensor over a 4-hour period. The transmission rate is modelled by the function

D(t)=1.25t0.5t2+4,0≤t≤4 D(t) = \frac{1.25^t}{\sqrt{0.5t^2 + 4}}, \quad 0 \le t \le 4 D(t)=0.5t2+4​1.25t​,0≤t≤4
a.

Complete the table below, giving the values of D(t)D(t)D(t) to 3 decimal places.

ttt01234
D(t)D(t)D(t)0.5000.6380.705
[2]
b.

Use the trapezium rule, with all the values of D(t)D(t)D(t) from the completed table, to find an approximate value for the total data transmitted,

∫041.25t0.5t2+4 dt \int_{0}^{4} \frac{1.25^t}{\sqrt{0.5t^2 + 4}} \, dt ∫04​0.5t2+4​1.25t​dt
[5]
Markscheme

11.9 The Trapezium Rule Questions

  1. A Level
  2. /Maths
  3. /11.9 The Trapezium Rule

44 exam-style questions on Edexcel A Level Maths 11.9 The Trapezium Rule. Each one has a worked solution and a mark scheme showing where the marks go.

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