The vertical velocity vvv of a test projectile, in m s−1\text{m s}^{-1}m s−1, is modelled by the function v(t)=t(21−t)v(t) = \sqrt{t}(21 - t)v(t)=t(21−t) for t≥0t \ge 0t≥0, where ttt is the time in seconds after launch.
Find, using calculus, the time ttt at which the projectile reaches its maximum vertical velocity.
A graph of vvv against ttt shows a region R1R_1R1 bounded by the curve and the ttt-axis between t=0t = 0t=0 and the point where the velocity first returns to zero (t=21t = 21t=21). A second region R2R_2R2 is bounded by the curve, the ttt-axis, and the vertical line t=Kt = Kt=K, where K>21K > 21K>21.
Given that the area of R1R_1R1 is equal to the area of R2R_2R2, use calculus to determine the exact value of KKK.
Practise Edexcel A Level Maths 11.8 Finding Areas with exam-style questions for A Level Maths. 28 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.
