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11.5 Integration by Substitution

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Question 22

Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln⁡2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln2​6−exex​dx

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Markscheme

11.5 Integration by Substitution Questions

  1. A Level
  2. /Maths
  3. /11.5 Integration by Substitution

59 exam-style questions on Edexcel A Level Maths 11.5 Integration by Substitution. Each one has a worked solution and a mark scheme showing where the marks go.

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