Use the substitution u=6−exu = 6 - e^xu=6−ex to find ∫0ln2ex6−exdx\displaystyle \int_0^{\ln 2} \frac{e^x}{6 - e^x} dx∫0ln26−exexdx
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Markscheme
11.5 Integration by Substitution Questions
59 exam-style questions on Edexcel A Level Maths 11.5 Integration by Substitution. Each one has a worked solution and a mark scheme showing where the marks go.