Use the substitution x=sinux = \sin ux=sinu to find ∫02211−x2dx\displaystyle \int_0^{\frac{\sqrt{2}}{2}} \frac{1}{\sqrt{1-x^2}} dx∫0221−x21dx
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Markscheme
11.5 Integration by Substitution Questions
59 exam-style questions on Edexcel A Level Maths 11.5 Integration by Substitution. Each one has a worked solution and a mark scheme showing where the marks go.