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11.5 Integration by Substitution

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Question 13

Use the substitution x=sin⁡ux = \sin ux=sinu to find ∫02211−x2dx\displaystyle \int_0^{\frac{\sqrt{2}}{2}} \frac{1}{\sqrt{1-x^2}} dx∫022​​​1−x2​1​dx

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Markscheme

11.5 Integration by Substitution Questions

  1. A Level
  2. /Maths
  3. /11.5 Integration by Substitution

59 exam-style questions on Edexcel A Level Maths 11.5 Integration by Substitution. Each one has a worked solution and a mark scheme showing where the marks go.

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