11.4 Reverse Chain Rule

Question 4

In a biochemical model, the rate of increase of a substance's concentration, $C$ , with respect to time, $t$ , is given by $dCdt=12t22t3+A\displaystyle \frac{dC}{dt} = \frac{12t^2}{2t^3 + A}$ , where $A\,$ is a positive constant.

a.

Find

\int \frac{12t^2}{2t^3 + A} \, dt

[2]

b.

Given also that

\int_{1}^{3} \frac{12t^2}{2t^3 + A} \, dt = \ln 196

find the value of $A$ .

[5]

11.4 Reverse Chain Rule

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Question 4

In a biochemical model, the rate of increase of a substance's concentration, $C$ , with respect to time, $t$ , is given by $dCdt=12t22t3+A\displaystyle \frac{dC}{dt} = \frac{12t^2}{2t^3 + A}$ , where $A\,$ is a positive constant.

a.

Find

\int \frac{12t^2}{2t^3 + A} \, dt

[2]

b.

Given also that

\int_{1}^{3} \frac{12t^2}{2t^3 + A} \, dt = \ln 196

find the value of $A$ .

[5]

11.4 Reverse Chain Rule

Question 4

Markscheme

11.4 Reverse Chain Rule

Question 4

Markscheme

11.4 Reverse Chain Rule

Question 4

11.4 Reverse Chain Rule Questions

11.4 Reverse Chain Rule

Question 4

11.4 Reverse Chain Rule Questions