The yield efficiency of a thermal generator, E(τ)E(\tau)E(τ), is given by the function
E(τ)=42τ2−17τ+156τ−5 E(\tau) = \frac{42\tau^2 - 17\tau + 15}{6\tau - 5} E(τ)=6τ−542τ2−17τ+15where τ>1\tau > 1τ>1 is the operating temperature factor. This expression can be rewritten in the form Aτ+B+C6τ−5A\tau + B + \frac{C}{6\tau - 5}Aτ+B+6τ−5C.
State the value of AAA.
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671542 6 \quad\quad 7 \quad\quad 15 \quad\quad 42 671542368 exam-style questions on Edexcel A Level Maths Algebraic Methods, covering 1.1 Proof by Contradiction, 1.2 Algebraic Fractions, 1.3 Partial Fractions, 1.4 Repeated Factors, and 1.5 Algebraic Division. Each one has a worked solution and a mark scheme showing where the marks go.