An anchoring force P\mathbf{P}P of magnitude 120 N is applied to a structural joint. The force acts in the third quadrant relative to the standard unit vectors i\mathbf{i}i (pointing right) and j\mathbf{j}j (pointing upwards). The direction of the force makes an angle of 25∘ 25^\circ\,25∘ with the negative yyy-axis.
The force can be expressed as a vector [PxPy] N\begin{bmatrix} P_x \\ P_y \end{bmatrix} \text{ N}[PxPy] N.
Find the correct expression for PyP_yPy.
Py=120cos25∘P_y = 120 \cos 25^\circPy=120cos25∘
Py=−120sin25∘P_y = -120 \sin 25^\circPy=−120sin25∘
Py=−120cos25∘P_y = -120 \cos 25^\circPy=−120cos25∘
Py=120sin25∘P_y = 120 \sin 25^\circPy=120sin25∘
Practise Edexcel A Level Maths Resolving Forces with exam-style questions for A Level Maths. 12 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.
