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Projection at Any Angle

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Question 47

In this question, use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.

A pyrotechnic shell is fired from a launch tube at ground level with an initial velocity of 21 m s−121 \text{ m s}^{-1}21 m s−1 at an angle α\alphaα to the horizontal.

The shell reaches a maximum vertical height of HHH metres.

a.

Show that

H=22.5sin⁡2α H = 22.5 \sin^2 \alpha H=22.5sin2α
[3]
b.

In a specific display, the launch angle is constrained such that 0∘≤α≤60∘0^\circ \le \alpha \le 60^\circ0∘≤α≤60∘. Determine the maximum possible height HHH the shell can reach under these conditions.

[3]
c.

A technician suggests that using a more massive shell would result in a lower maximum vertical height when launched with the same velocity and angle. Explain whether the technician is correct according to the standard projectile model.

[1]

Projection at Any Angle Questions

  1. A Level
  2. /Maths
  3. /Projection at Any Angle

Practise Edexcel A Level Maths Projection at Any Angle with exam-style questions for A Level Maths. 62 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.

Question bank