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2 Unit AS 2: Applied Mathematics

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Question 260

In this question, use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.

A precision sensor module is dragged across a rough horizontal laboratory floor. A horizontal tension of magnitude FFF newtons is applied to the module by a robotic arm.

The module moves with a constant acceleration of 0.75 m s−20.75 \text{ m s}^{-2}0.75 m s−2.

The sensor module has a weight of 4.41 N4.41 \text{ N}4.41 N.

The only resistance to motion is the friction between the module and the floor.

The coefficient of friction between the module and the floor is 0.220.220.22.

Find FFF.

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2 Unit AS 2: Applied Mathematics Questions

  1. A Level
  2. /Maths
  3. /2 Unit AS 2: Applied Mathematics

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