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2 Unit AS 2: Applied Mathematics

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Question 68

In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2.

A man of mass 75 kg stands on the floor of a lift. The total mass of the lift and its contents, including the man, is 600 kg.

The lift accelerates vertically upwards at 0.8 m s−2^{-2}−2.

a.

Find the tension in the lift cable.

[2]
b.

Find the magnitude of the normal reaction of the lift floor on the man.

[2]
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2 Unit AS 2: Applied Mathematics Questions

  1. A Level
  2. /Maths
  3. /2 Unit AS 2: Applied Mathematics

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