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1.4.6 Trigonometry

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Question 15
i.

Determine the values of x x\,x in the interval 0<x<π 0 < x < \pi\,0<x<π that satisfy the equation:

(3x−7.5)(3cosec⁡x−2)=0 (3x - 7.5)(\sqrt{3}\operatorname{cosec} x - 2) = 0 (3x−7.5)(3​cosecx−2)=0
[3]
ii.

Solve, for 0∘<θ<360∘0^\circ < \theta < 360^\circ0∘<θ<360∘, the equation:

3cos⁡2θ+8cos⁡θ=1 3\cos 2\theta + 8\cos \theta = 1 3cos2θ+8cosθ=1

Give your answers to one decimal place.

[5]

1.4.6 Trigonometry Questions

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