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In a right-angled triangle, [...]\text{[...]}[...], cosθ=adjacenthypotenuse\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent and tanθ=oppositeadjacent\tan\theta=\frac{\text{opposite}}{\text{adjacent}}tanθ=adjacentopposite.
Upwards from a horizontal line.
248∘248^\circ248∘
It produces a horizontal phase shift.
In a right-angled triangle, sinθ=oppositehypotenuse\boxed{\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}}sinθ=hypotenuseopposite, cosθ=adjacenthypotenuse\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}cosθ=hypotenuseadjacent and tanθ=oppositeadjacent\tan\theta=\frac{\text{opposite}}{\text{adjacent}}tanθ=adjacentopposite.
Card 1 of 23
3.4.8 Trigonometry (A-level only) Flashcards
23 flashcards on CCEA A Level Maths 3.4.8 Trigonometry (A-level only): the key formulae, methods and definitions you need to recall for AS 1, AS 2, A2 1 and A2 2.