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3.4.6 Trigonometry (A-level only)

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Question 11

A high-precision docking system in an aerospace facility uses two automated parallel assemblies, A A\,A and BBB, which oscillate vertically to dampen vibrations during a calibration cycle of 6π 6\pi\,6π minutes. At time t t\,t minutes after the cycle begins, the height hA h_A\,hA​ metres of assembly A A\,A above the hangar floor is given by

hA=26.8−7sin⁡t h_A = 26.8 - 7\sin t hA​=26.8−7sint

At time t t\,t minutes after the cycle begins, the height hB h_B\,hB​ metres of assembly B B\,B above the hangar floor is given by

hB=7.4−5cos⁡t h_B = 7.4 - 5\cos t hB​=7.4−5cost
a.

Show that the initial vertical separation between assembly A A\,A and assembly B B\,B is 24.4 metres.

[3]
b.

Show that the distance Δ \Delta\,Δ metres between the two assemblies at time t t\,t is given by

Δ=19.4+Rcos⁡(t+α) \Delta = 19.4 + R\cos(t + \alpha) Δ=19.4+Rcos(t+α)

where R R\,R and α \alpha\,α are positive constants to be found. Give R R\,R in surd form and α \alpha\,α in radians to two decimal places.

[4]
c.

Hence, determine the minimum vertical distance between the two assemblies. Give your answer to the nearest centimetre.

[3]

3.4.6 Trigonometry (A-level only) Questions

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