The first three terms, in ascending powers of xxx, of the binomial expansion of (16+5x)12(16 + 5x)^{\frac{1}{2}}(16+5x)21 are given by
(16+5x)12≈a+58x−25512x2 (16 + 5x)^{\frac{1}{2}} \approx a + \frac{5}{8}x - \frac{25}{512}x^2 (16+5x)21≈a+85x−51225x2where aaa is a constant.
State the range of values of xxx for which this expansion is valid.
Choose from the options below:
∣x∣<516∣x∣<165∣x∣<4∣x∣<1 |x| < \frac{5}{16} \quad |x| < \frac{16}{5} \quad |x| < 4 \quad |x| < 1 ∣x∣<165∣x∣<516∣x∣<4∣x∣<1Find the value of aaa.
Choose from the options below:
14816 1 \quad 4 \quad 8 \quad 16 14816