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2.2 Kinematics

2.2 Kinematics

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Question 52

At time t=0t=0t=0, a particle has position vector (2i+4j)(2\mathbf{i}+4\mathbf{j})(2i+4j) m, velocity (5i−2j)(5\mathbf{i}-2\mathbf{j})(5i−2j) m s−1^{-1}−1 and constant acceleration (−i+3j)(-\mathbf{i}+3\mathbf{j})(−i+3j) m s−2^{-2}−2.

a.

Find the velocity of the particle when t=4t=4t=4.

[2]
b.

Find the position vector of the particle when t=4t=4t=4.

[3]
c.

Find the speed of the particle when t=4t=4t=4.

[2]
Markscheme

2.2 Kinematics Questions

  1. A Level
  2. /Maths
  3. /2.2 Kinematics

85 exam-style questions on CCEA A Level Maths 2.2 Kinematics, covering 2.2.1 Kinematics, 2.2.2 Kinematics, 2.2.3 Kinematics, and 2.2.4 Kinematics. Each one has a worked solution and a mark scheme showing where the marks go.

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