In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2.
A particle is projected from the origin with velocity (12i+16j)(12\mathbf{i} + 16\mathbf{j})(12i+16j) m s−1^{-1}−1, where i\mathbf{i}i is horizontal and j\mathbf{j}j is vertically upwards.
Find the position vector of the particle at the instant when it is moving at 45° 45°\,45° below the horizontal.
91 exam-style questions on CCEA A Level Maths 4.1.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.