The acceleration of a particle at time t t\,t seconds is a=4t3i−6t2j m s−2\mathbf a=4t^3\mathbf i-6t^2\mathbf j\text{ m s}^{-2}a=4t3i−6t2j m s−2. At t=0t=0t=0 its velocity is (2i+3j) m s−1(2\mathbf i+3\mathbf j)\text{ m s}^{-1}(2i+3j) m s−1 and its position vector is the zero vector.
Find the velocity when t=2t=2t=2.
Find the displacement vector during the first 2 seconds.
61 exam-style questions on CCEA A Level Maths 4.1.1 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.