The acceleration of a particle at time t t\,t seconds is a=6ti+4j m s−2\mathbf a=6t\mathbf i+4\mathbf j\text{ m s}^{-2}a=6ti+4j m s−2. Initially its velocity is (2i−j) m s−1(2\mathbf i-\mathbf j)\text{ m s}^{-1}(2i−j) m s−1 and its position vector is (3i+2j)(3\mathbf i+2\mathbf j)(3i+2j) m.
Find the velocity at time ttt.
Find the position vector when t=2t=2t=2.
61 exam-style questions on CCEA A Level Maths 4.1.1 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.