The acceleration of a particle after t t\,t seconds is given by (4t−8) ms−2(4t - 8) \text{ ms}^{-2}(4t−8) ms−2. Given the velocity (vvv) of the particle is 6 ms-1 when t=0t = 0t=0.
Find v v\,v in terms of ttt.
Find the distance between the two points the particle is instantaneously at rest.
61 exam-style questions on CCEA A Level Maths 4.1.1 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.