At time t t\,t seconds a particle has velocity v=4ti−3j\mathbf{v} = 4t\mathbf{i} - 3\mathbf{j}v=4ti−3j m s−1^{-1}−1.
Find the acceleration of the particle when t=2t = 2t=2.
Circle your answer.
4i4\mathbf{i}4i m s−2^{-2}−2
8i8\mathbf{i}8i m s−2^{-2}−2
4i−3j4\mathbf{i} - 3\mathbf{j}4i−3j m s−2^{-2}−2
8i−3j8\mathbf{i} - 3\mathbf{j}8i−3j m s−2^{-2}−2
204 exam-style questions on CCEA A Level Maths 4.1 Kinematics (A-level only), covering 4.1.1 Kinematics (A-level only), 4.1.2 Kinematics (A-level only), and 4.1.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.