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4.1 Kinematics (A-level only)

4.1 Kinematics (A-level only)

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Question 92

The acceleration of a particle at time t t\,t seconds is a=6ti+4j m s−2\mathbf a=6t\mathbf i+4\mathbf j\text{ m s}^{-2}a=6ti+4j m s−2. Initially its velocity is (2i−j) m s−1(2\mathbf i-\mathbf j)\text{ m s}^{-1}(2i−j) m s−1 and its position vector is (3i+2j)(3\mathbf i+2\mathbf j)(3i+2j) m.

a.

Find the velocity at time ttt.

[3]
b.

Find the position vector when t=2t=2t=2.

[4]
Markscheme

4.1 Kinematics (A-level only) Questions

  1. A Level
  2. /Maths
  3. /4.1 Kinematics (A-level only)

204 exam-style questions on CCEA A Level Maths 4.1 Kinematics (A-level only), covering 4.1.1 Kinematics (A-level only), 4.1.2 Kinematics (A-level only), and 4.1.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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