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1.7 Integration

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Question 74

A marine biologist models the rate of change of nutrient density DDD with respect to the depth hhh (in meters) of a water column as:

dDdh=7h5−414h6,h>0 \frac{dD}{dh} = \frac{7h^5 - 4}{14h^6}, \quad h > 0 dhdD​=14h67h5−4​,h>0

Find an expression for DDD in terms of hhh, giving your answer in its simplest form.

[4]

1.7 Integration Questions

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