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3.6.4 Integration (A-level only)

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Question 67
i.

Find

∫x2e2x dx \int x^2e^{2x} \, dx ∫x2e2xdx
[4]
ii.

Use the substitution u=2x+1u = \sqrt{2x + 1}u=2x+1​ to show that

∫12x2x+1 dx=2(2x+1)12(Ax+B)+k \int \frac{12x}{\sqrt{2x + 1}} \, dx = 2(2x + 1)^{\frac{1}{2}}(Ax + B) + k ∫2x+1​12x​dx=2(2x+1)21​(Ax+B)+k

where AAA and BBB are integers to be found and kkk is an arbitrary constant.

[6]

3.6.4 Integration (A-level only) Questions

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