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3.6.4 Integration (A-level only)
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Question 61
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∫0π(xsin2x) dx=−π2 \int_{0}^{\pi} (x \sin 2x) \, dx = -\frac{\pi}{2}
∫
0
π
(
x
sin
2
x
)
d
x
=
−
2
π
[5]
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3.6.4 Integration (A-level only) Questions
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3.6.4 Integration (A-level only)
