Show that
∫0π(xsin2x) dx=−π2 \int_{0}^{\pi} (x \sin 2x) \, dx = -\frac{\pi}{2} ∫0π(xsin2x)dx=−2π119 exam-style questions on CCEA A Level Maths 3.6.4 Integration (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.